Price mechanism is a feature of
The expenses on advertising is called
The rate of deforestation is high in
The term ‘Green Revolution’ was coined by

Solution
The term 'Green Revolution' was first used in 1968 by former United States Agency for International Development (USAID)Director William Gaud.
In a class Rajan got the 11th rank and he was 31st from the bottom of the list of boys passed. Three boys did not take the examination and one failed. What is the total strength of the class?

Solution
Total strength of the class = 10 + 30 + 1 + 3 + 1 = 45
What is the second largest component in milk?

Solution
Components of Milk: Water (87 per cent), Carbohydrate (4.9 per cent), Fat (3.4 per cent), Protein (3.3 per cent), and so on.
The percentage of oxygen in air is approximately

Solution
Composition of air is as given below:
Nitrogen: 78.08 per cent
Oxygen: 20.94 per cent
Argon: 0.93 per cent
Carbondioxdide : 0.03 per cent
Neon: 0.0018 per cent
Helium: 0.0005 per cent
Ozone: 0.00006 per cent
Hydrogen: 0.00005 per cent
Find the wrong number in the series:
7,28,63,124,215,342

Solution
Which of the following is not an insectivorous plant?

Solution
Insectivorous plants are Aldrovanda, Archaeamphora, Brocchinia, Byblis, Catopsis,
Dionaea, Drosera, Genlisea, Heliamphora, Nepenthes, Palaeoaldrovanda, Philcoxia,
Roridule, Sarracenia , Stylidium, Triphyophyllum, Utricularia etc
Which one set of letters when sequentially placed at the gaps in the given letter series shall complete it ?
an – nn – ana – na – nan – a

Solution
an a nn a / ana n na / a nan n a
While purchasing one item costing Rs 400, one has to pay sales tax at 7% and on another costing Rs 6400, the sales tax was 9%. The per cent of sales tax one has to pay, taking these items together on an average is

Solution
Sales tax on the article sold at Rs 400
=\(frac{400times 7}{100}= Rs 28\)Sales tax on the article sold at Rs 6400
=\(frac{6400times 9}{100}= Rs 576\)
Total tax = 28 + 576 = Rs 604
Percentage sales tax =\(frac{604}{6800}times 100\)
\(=frac{151}{17}=8frac{15}{17}%\)%
Ram aims to score an average of 80 marks in quarterly and halfyearly exams. But his average in quarterly is 3 marks less than his target and that in halfyearly is 2 marks more than his aim. The difference between the total marks scored in both the exams is 25. Total marks aimed by Ram is

Solution
Let each exam be of 100 marks.
∴ Difference = 82  77 = 5
∴ 5 = 100 marks
∴ 25 = 500 marks
∴ Required marks = 500 × ^{80}⁄_{100} = 400
The total number of students of a school was 660. The ratio between boys and girls was 13 : 9. After some days, 30 girls joined the school and some boys left the school and new ratio between boys and girls became 6 : 5. The number of boys who left the school is

Solution
In the first case, Boys = 660 In the first case, Boys = 660 x ^{13}⁄_{22} = 390
Girls = 660 × ^{9}⁄_{22} = 270
Let x boys leave the school.
Now, according to the question\(frac{390x}{270+30}=frac{6}{5}\)
⇒ 390  x= 360
⇒ x = 390  360 = 30
A certain scheme of investment in simple interest declares that it trebles the investment in 8 years. If you want to quadruple your money through that scheme, you have to invest it for

Solution
Principal = Rs x, Amount = Rs 3x
S I = Rs 2x\(Rate=frac{SItimes 100}{principal times Rate}=frac{2xtimes 100}{xtimes 25}= 25\)%
Case II
\(Time=frac{SItimes 100}{principal times Rate}=frac{3xtimes 100}{xtimes 25}= 12: years\)
The value of cot θ tan(90° θ) – sec(900 θ) cosec θ + (sin^{2} 25°+ sin^{2} 65°) +\(\sqrt{3}\) (tan 5°. tan 15°. tan 30°. tan75°. tan 85°) is

Solution
cotθ. tan (90°  θ) sec (90°  θ). cosecθ + (sin^{2}25° + sin^{2} 65°) + \(sqrt{3}\) (tan5°. tan 15°. tan30°. tan 75°. tan 85°)
= cotθ. cotθ  cosecθ. cosecθ + (sin^{2} 25° + cos^{2} 25°)+\(sqrt{3}\) (tan 5°. cot 5°. tan 15°. cot 15°. tan 30°)
= (cot^{2}θ cosec^{2}θ)+ (sin^{2} 25° + cos^{2} 25°) + \(sqrt{3}\)×\(frac{1}{sqrt{3}}\)=1+1+1=1
[sin(90°θ) = cosθ; cosec^{2}θ  cot^{2}θ = 1; tan
(90°  θ) = cotθ: sec (90°  θ) = cosecθ]
If day before yesterday was Wednesday, when will Sunday be ?

Solution
Today is Friday and Sunday will be day after tomorrow.
In a row of 16 boys, when Prakash was shifted by two places towards the left, he became 7th from the left end. What was his earlier position from the right end of the row ?

Solution
∴ Earlier position of Prakash from the right
end = 169+1 = 8th
M and F are a married couple. A and Bare sisters. A is the sister of F. Who is B to M ?

Solution
Clearly, B is sisterinlaw of M.
Directions: From among the given alternatives, select the one in which the set of numbers is most like the set of numbers given in the question.
Given set: (10, 12, 15)

Solution
Directions: A series is given with one (or more) term missing. Choose the correct alternative from the given ones that will complete the series.
14, 21, 30, 41, 54, ?

Solution