pH value between 6.57.5 makes the soil

Solution
pH value between < 7 is acidic while pH = 7 is neutral and pH > 7 is Basic.
So Soil with pH 6.5 to 7.5 is considered neutral.
Directions: In the following sentences are given with blanks to be filled in with the appropriate word(s). Four alternatives are suggested for each question. Choose the correct alternative out of the four.
Napoleon’s army________to the Russian soldiers without any fight.

Solution
capitulated
Directions: In the following sentences are given with blanks to be filled in with the appropriate word(s). Four alternatives are suggested for each question. Choose the correct alternative out of the four.
For____ sake don’t tell it to others.

Solution
heven's
Directions: In the following sentences are given with blanks to be filled in with the appropriate word(s). Four alternatives are suggested for each question. Choose the correct alternative out of the four.
Mahesh showed an for sports at a very early stage.

Solution
The word 'Aptitude (Noun)' means: natural ability or skill at doing something; talent.
Look at the sentenee : He showed a natural aptitude for the studies.
Directions: In the following sentences are given with blanks to be filled in with the appropriate word(s). Four alternatives are suggested for each question. Choose the correct alternative out of the four.
He is weak_________he does a lot of work.

Solution
yet
Directions: In the following sentences are given with blanks to be filled in with the appropriate word(s). Four alternatives are suggested for each question. Choose the correct alternative out of the four.
If______ a doctor, I would serve the poor.

Solution
were
If \(n+\frac{2}{3}n+\frac{1}{2}n+\frac{1}{7}n=97\) then the value of n is

Solution
\(n+\frac{2n}{3}+\frac{n}{2}+\frac{n}{7}=97\)
\(\Rightarrow \frac{42n + 28n + 21n + 6n}{42}=97\)
\(\Rightarrow\frac{97n}{42}=97\Rightarrow n=\frac{97\times 42}{97}= 42\)

Solution
Expression = \(\left ( \sqrt{2}+\sqrt{72\sqrt{10}} \right )\)
\(=\sqrt{2}+\sqrt{72\times \sqrt{5}\times \sqrt{2}}\)
\(=\sqrt{2}+\sqrt{(\sqrt{5})^{2}+(\sqrt{2})^{2}2\times \sqrt{5}\times \sqrt{2}}\)
\(=\sqrt{2}+\sqrt{(\sqrt{5}\sqrt{2})^{2}}\)
\(=\sqrt{2}+\sqrt{5}\sqrt{2}=\sqrt{5}\)
If \(\sqrt{3}\) =1.732, is given, then the value of \(\frac{2+\sqrt{3}}{2\sqrt{3}}\) is

Solution
Expression
\(\frac{2+\sqrt{3}}{2\sqrt{3}}=\frac{(2+\sqrt{3})(2+\sqrt{3})}{(2\sqrt{3})(2+\sqrt{3})}\)
(On rationalising the denominator)\(=\frac{\left ( 2+\sqrt{3} \right )^{2}}{43}\left ( 2+\sqrt{3} \right )^{2}\)
\(=2^{2}+\left ( \sqrt{3} \right )^{2}+2\times 2\sqrt{3}\)
=4+3+4\(\sqrt{3}\)
= 7 + 4 × 1.732 = 7 + 6.928
= 13.928
Directions : Select the related letters/word/number /figure from the given alternatives.
14 : 20 : : 16 : ?

Solution
From question:\(\frac{14}{20}=\frac{16}{x}\Rightarrow x\)
\(=\frac{16}{14}\times 20=\frac{160}{7}=22.9=23\)