In a certain code, if CARPET is writeen as B Z Q O D S, then how would POCKET be written in that code?

Solution
Directions: In what order would you find the following words in the dictionary?
1. Spat 2. Spit
3. Spout 4. Spopt

Solution
Arrangement of words as per dictionary :
1. Spat
↓
2. Spit
↓
4. Spot
↓
3. Spout
Directions: In what order would you find the following words in the dictionary?
1. Morning 2. Mourn
3. Marine 4. Miracle

Solution
Arrangement of words as per dictionary :
3. Marine
↓
4. Miracle
↓
1. Morning
↓
2. Mourn
Directions: In what order would you find the following words in the dictionary?
1. Please 2. Pleasure
3. Pleasant 4. Plead

Solution
Arrangement of words as per dictionary :
4. Plead
↓
3. Pleasant
↓
1. Please
↓
2. Pleasure
My age is 2 year less then twice that of my sister. If I am 16 years old, how old is my sister?

Solution
Suppose the age of my sister is x years
According to question
2x  2 = 16
⇒ 2x = 18
∴ x = 9 years
Find the largest number which leaves the same remainder when dividing 98, 120 and 153

Solution
Let the remainder be x.
Required number
= HCF of (98  x), (120  x) and (153 x)
= HCF of 22, 33 and 55 = 11
Which of the following fractions is the smallest?

Solution
\(\frac{5}{8}\)= 0.625 , \(\frac{7}{10}\) =0.7
\(\frac{3}{4}\) =0.75 ,\(\frac{9}{16}\) = 0.5625
∴ Smallest fraction = ^{9}⁄_{16}
The sum of the digits of a two digit number is 11. On adding 27 to the given number its digits are reversed. Find the number

Solution
Suppose the number
= 1Ox + y
x + y =11 (i)
(1Ox + y) + 27 = 1Oy + x
⇒ 10x  x + y lOy = 27
⇒ 9x 9y = 27
⇒ x  y = 3 (ii)
⇒ x = 4 and y =7
=10x + y = 40 + 7 = 47
Find the area of triangle whose base in 10 cm and height is 26 cm

Solution
Area of triangle
= ^{1}⁄_{2} × Base × Height
= ^{1}⁄_{2}×10× 26 =130sq. cm
If the interest is compounded annually find the C.I. on ₹ 2,000 for 3 yrs at 10%

Solution
Compound Interest
\(=AP=p\left ( \frac{1+R}{100} \right )^{2}p\)
\(=2000\left [ \left ( \frac{1+10}{100} \right )^{3}1 \right ]\)
\(=2000\left [ \frac{11}{10}\times \frac{11}{10}\times \frac{11}{10}1 \right ]\)
\(=2000\left ( \frac{13311000}{1000} \right )\)
\(\frac{2000\times 331}{1000} = Rs.662\)