The donor of AB blood group can donate to recipient of blood group

Solution
The blood group AB is called Universal acceptor. The donor of AB blood group can donate blood to the person having AB blood group. AB blood group carries both A and B antigens but no antibody.Blood consists of an aqueous solution of inorganic ions and organic molecules in which are suspended red blood particles.
Synovial fluid is found in the

Solution
Synovial fluid is a viscous fluid lubricating joints and tendon sheaths. Synovial membrane is a dense membrane of connnective tissue secreting synovial fluid.
Ribosome’s main activity is

Solution
The main activity of Ribosome is protein synthesis. Ribosome refers to each of the minute particles consisting of Ribonucleic acid and associated proteins found in the cytoplasm of living cells
The Parliament consists of the

Solution
Parliament is the national legislature of the Indian Union, It is a bicameral legislature and consists of Prest dent, the Rajya Sabha (the Upper House : Council of States) and the Lok Sabha (the Lower House : House of People). In matter of legtslation, both Houses have coequal powers except in the case of Money Bills With respect to which the Lok Sabha reigns supreme. The President is an integral part of Parltament and all Bills passed by it must receive his assent be fore becoming laws. The Prestdent summons and prorogues the Parliament and dissolves the Lok Sabha.
A train runs at the speed of 72 km per hour. The distance between any two stations is 42km and the train stops at each stations for 5 minutes. Then the time taken by train to go 350 km is

Solution
There will be 8 stations of length 42km each in a distance of 350 km.
Time taken in covering 42 km\(=\frac{42}{72} \times 60\: minutes\)
= 35 minutes Actual time = 35 + 5
= 40 minutes
Time taken in covering 8 stations
= 8 × 40 = 320 minutes
= 5 hours 20 minutes
Remaining dtstance = 350  8 ×42 = 14km
Time taken in covering remammg 14 km = \(\frac{14}{72}\) × 60 minutes
\(=\frac{35}{3}=11\frac{2}{3}\: Minutes\)
=11 minutes 40 seconds
∴Total time = 5 hours 20 minutes + 11 minutes 40 seconds
= 5 hours 31 minutes 40 seconds
A two digit is such that when it is divided by the largest single digit prime number leaves remainder 4. If the difference of the two digits is 4 then the number is

Solution
If Number = 95, then 95 =4 and
7)95(13\(\frac{7}{25}\)
\(\frac{21}{4}\)
Remainder = 4
There is a path. 1m wide. outside a rectangular field of 16m length and 11m breadth. Then the total area of the path is

Solution
Length of field with path
= 16 + 2 × 1 = 18 metre
Width of field with path
= 11 + 2 × 1 = 13 metre
Area of field with path
= 18 × 13 = 234 sq. metre
Area of field without path
= 16 × 11 = 176 sq. metre
Area of path
= 234  176 = 58 sq. metre
Consider the natural number 88935. Then the least natural number by which we can divide or multiply the number to make it a square number is

Solution
∴ 88935=5×3×7^{2}×11^{2}
Required number = 15
Let a_{1},a_{2}…….a_{7}be arbitrary different positive integers. taking one value at a time from 1.2…..7. The number (a_{1}– 1) (a_{2}– 2) …. (a_{7}– 7)

Solution
If a_{1}= 1, a_{2}= 2,......
(a_{1} 1) (a_{2} 2) (a_{3}  3)......
(a_{7}7) = 0
If a_{1} = 7,a_{2} = 6, a_{3} = 5,....
(a_{1} 1) (a_{2} 2) (a_{3}  3)....
(a_{7} 7) = 6 × 4 × 3 × 0 ×......
=0
5 pencils and 4 erasers cost Rs. 13 whereas 9 pencils and 5 erasers cost Rs. 19. Then the price of 6 pencils and 3 erasers is

Solution
Price of 1 pencil = Rs. x
Price of 1 rubber = Rs. Y
∴ 5x+ 4y= 13.....(i)
9x + 5y = 19......(ii)
By equation (1) × 5  (11) × 4,⇒x= 1
From equation (i),
5 × 1 + 4y = 13
⇒4y= 135=8
⇒y=2
∴6x+3y=6+3×2=Rs.12